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<HW 29 Section 12.1-12.3 The Elastic Curve The cantilever beam ABC (Figure 1)shown is composed of two solid cylindrical secti
Part A - Internal bending moments in beam ABC After drawing a free-body diagram, the first step in analyzing the deflections
Part B - Moments of inertia for portion AB and portion BC of the beam Determine the moments of inertia for AB, IAB, and BC, I
Part C - Radius of curvature for AB and BC Determine the radius of curvature for AB, PAB, and for BC, PBC. Express your answe
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Part A Free Body Diagram is; ;) Section АВ га MAp 64 kip .fl 69 iP. 1- i Section ВС 64 kip . 56 up.ee _M BC A ме : 44+ 56 MBPart B 4 Moment of Inerdia for Circular Section TC D 64 » Section AB 0,- 2.00 in Moment of Inertia of section AB I AB tt d, 4part c simple bending equation is, E U P 1 i, pa ET M wher, P- Radia . Pastelere Youngs Modulus I M Moment of Inertia - Bend14 Section be MBC = 125 kip.ft I BC = 63.617 in 4 Radius of Carvatur of BC lee Ex IBC MBC 2.8710 x 12² X10x 12 x 63.617*12 -

The given cantilever section was solved for bending moment, moment of inertia and radius of curvature

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