Question

Out of 600 people sampled, 474 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to four places <p<

Answer 1

The 99% confidence interval for the true population proportion is 0.7471<p<0.8328

Complete solution is given in attached image:

ble need interval .2_وو to for of Construct confidence the true population people with Kids proportion X= no. of people na Sample size having kids 474 600 R Х Sample proportion = pa 0.79 a=0.01 is The critical Ze = Zato value for 2.576 confidence interval is .calculated as PI-P fe-za CI. p(-p) P + Ze 0-79*0-21 -79-2-576 0.79 + 2.576 0.79*0.21 (0.7471, O. 0.8328) Therefore based data provided, the gg % confidence interval for the population proportion is 0.7471 < p < 0.8328

Thank You.