Question

The current in the vertical wire flows upward and its value is constant. Question 13 5 An object is located at a distance of 7.00 cm from a thin lens with a radius of curvature of 66.0 mm. The image of the object is inverted. Is the image real or virtual, and how far is the image from the lens? O Real, 6.24 cm Virtual, 6.24 cm Real, 116 cm O Virtual, 116 cm O Real, 2.2 cm Question 14 5p A concave spherical mirror with a radius of curvature of 100 cm generates an inverted image at a distance of 2.5 m from the mirror. What is the magnification of the image? O 1.5 512

Answer 1

13) As the refractive index of lens is not given,there is a mistake in the question. Actually instead of lens, mirror is to be used.

As the image is inverted, it means the mirror is concave mirror.

Given:

f = focal length = R/2 = -66mm/2 = -6.6/2 cm= -3.3cm

u = object distance = -7 cm

Let the image distance be v.

Using mirror equation:

$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\Rightarrow \frac{1}{v}+\frac{1}{-7}=\frac{1}{-3.3}$

$\Rightarrow \frac{1}{v}=\frac{1}{-3.3}+\frac{1}{7}$

$\Rightarrow v=\frac{1}{\frac{1}{-3.3}+\frac{1}{7}}=-6.24 cm$.

As the image distance is negative, it means the image formed is real.

Therefore, The image formed is real and at a distance 6.24 cm. [answer]

[correct option is the 1st option]