Question

A sociologist finds that in a random sample of 142 U.S. teenagers, 112 regularly use social...

A sociologist finds that in a random sample of 142 U.S. teenagers, 112 regularly use social media to communicate with their friends and family. Use the sample to construct a 90% confidence interval for the proportion of teenagers who regularly use social media to communicate with their friends and family.

What is the margin of error for the 90% confidence interval? Round to three decimal places.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

\hat{p}=\frac{x}{n}=\frac{ 112 }{ 142 }= 0.7887

E= Z*\sqrt{\frac{\hat{p}*(1-\hat{p})}{n}}= 1.645 *\sqrt{\frac{ 0.7887 * 0.2113 }{ 142 }}= 0.0564
Add a comment
Know the answer?
Add Answer to:
A sociologist finds that in a random sample of 142 U.S. teenagers, 112 regularly use social...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 13, A Gallup Youth Survey found that 54% of 502 randomly selected teenagers in the U.S....

    13, A Gallup Youth Survey found that 54% of 502 randomly selected teenagers in the U.S. said they got along very well with their parents. What is the number of teenagers in the sample who said that they get along very well with their parents? (4 points) a. b. Construct a 90% confidence interval to estimate the proportion of teenagers in the U.S. who get along very well with their parents. (Show your work or calculator command to get full...

  • a simple random of 256 college students showed that 142 of them agree with a certain...

    a simple random of 256 college students showed that 142 of them agree with a certain law. construct the 95% confidence interval estimate of the proportion of students who agree with this law a. state the critical value b. compute the margin of error c. state the confidence interval d. compute the minimum sample size that will keep the margin of error within 2%. use the information given in this problem

  • In an August 2012 Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12. The bootstrap distribution (based on 5,000 samp

    1. In an August 2012 Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12. The bootstrap distribution (based on 5,000 samples) is provided.  a). Would it be appropriate to use the normal distribution to construct the confidence interval in this situation? Explain briefly. b). The standard error from the bootstrap distribution is SE = 0.016. Use the normal distribution...

  • Confidence Interval: 1. A new Pew Research Center survey of 4,594 U.S. adults finds that 78%...

    Confidence Interval: 1. A new Pew Research Center survey of 4,594 U.S. adults finds that 78% of the public thinks it likely that social media platforms actively censor political views that those companies find objectionable. What is the value of n? What is the value of pˆp^ Compute the margin of error, E, that corresponds to a 95% confidence level. Compute the 95% confidence interval estimate of the population proportion p. Based on the results, can we safely conclude that...

  • Question 6 View Policies Current Attempt in Progress Use the normal distribution to find a confidence...

    Question 6 View Policies Current Attempt in Progress Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 90% confidence interval for p given that p = 0.34 and n = 500. wers for the margin of error and the confidence interval Round your answer for the best...

  • In a random sample of 500 U.S. citizens, 268 said that they plan to vote in...

    In a random sample of 500 U.S. citizens, 268 said that they plan to vote in the upcoming election. a. Construct a 90% confidence interval for the proportion of all U.S. citizens who would say they plan to vote in the upcoming election. b. Explain why the interval does or does not indicate that a majority of U.S. citizens would say they plan to vote in the upcoming election. c. Explain why the interval does or does not indicate the...

  • In random, independent samples of 200 adults and 400 teenagers who watched a certain television show,...

    In random, independent samples of 200 adults and 400 teenagers who watched a certain television show, 98 adults and 224 teens indicated that they liked the show. Let p1 be the proportion of all adults watching the show who liked it, and let P2 be the proportion of all teens watching the show who liked it. Find a 90% confidence interval for pi-p2. Then complete the table below. carry your intermediate computations to at least three decimal places. Round your...

  • 1. A random sample of n measurements was selected from a population with standard deviation σ=13.6...

    1. A random sample of n measurements was selected from a population with standard deviation σ=13.6 and unknown mean μ. Calculate a 90 % confidence interval for μ for each of the following situations: (a) n=45, x¯¯¯=89.8 ≤μ≤ (b) n=70, x¯¯¯=89.8 ≤μ≤ (c) n=100, x¯¯¯=89.8 ≤μ≤ (d) In general, we can say that for the same confidence level, increasing the sample size the margin of error (width) of the confidence interval. (Enter: ''DECREASES'', ''DOES NOT CHANGE'' or ''INCREASES'', without the...

  • A researcher examined a random sample of 300 homes in a small city and found that...

    A researcher examined a random sample of 300 homes in a small city and found that 52 had solar panels installed on their roofs. Use the sample to construct a 99% confidence interval for the proportion of all homes in the city that have solar panels installed on their roofs. What is the margin of error for the 99% confidence interval? Round to three decimal places.

  • A researcher examined a random sample of 300 homes in a small city and found that...

    A researcher examined a random sample of 300 homes in a small city and found that 52 had solar panels installed on their roofs. Use the sample to construct a 99% confidence interval for the proportion of all homes in the city that have solar panels installed on their roofs. What is the margin of error for the 99% confidence interval? Round to three decimal places.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT