Question

X Groups of adults are randomly selected and arranged in groups of three. The random variable x is the number in the group wh
Find the mean of the random variable x. Select the correct choice below and, if necessary, fill in the answer box to complete
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Answer #1
x P(x) x * P(x) x^2 * P(x)
0 0.357 0 0
1 0.446 0.446 0.446
2 0.168 0.336 0.672
3 0.029 0.087 0.261
\sum x * P(x) = 0.869 \sum x^2 * P(x) = 1.379

Since, all probabilities are between 0 and 1 inclusive, and sum of all probabilities equal to 1, so this is a valid probabilitiy distribution.

Answer : A) Yes, the table shows a probability distribution.

The mean and standard deviation of the probabilitiy distribution are as follows :

\\ \mu = E(X) = \sum x * P(x) = 0.869 \\\\ => \mu = \bold {0.9} \text { (rounded to one decimal place)}

\\ \sigma= \sqrt {\sum x^2 * P(x) -\mu^2} = \sqrt {1.379 -(0.869)^2} = 0.7898 \\\\ => \sigma= \bold {0.8} \text { (rounded to one decimal place)}

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