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Silly-Sort(A,i,j) if A[i] > A[j] then exchange A[i] and A[j]; if i+1 >= j then return; k = floor(j-i+1)/3); Silly-Sort(A,i,j-k); Silly-Sort(A,i+k,j); Silly-Sort(A,i,j-k); (a) Argue (by induction) that if n is the length of A, then Silly- Sort(A,1,n) correctly sorts the input array A[1...n] (b) Give a recurrence relation for the worst-case run time of Silly-Sort and a tight bound on the worst-case run time (c) Compare this worst-case runtime with that of insertion sort, merge sort, heapsort and quicksort.
COMPLETE BigMerge public class BigMerge { /* * Returns j such that a[j][index[j]] is the minimum * of the set S={a[i][index[i]] for every i such that index[i]<a[i].length} * If the set S is empty, returns -1 * Runs in time a.length. * * NOTE: normally this would be private, but leave it * public so we can test it separately from your merge. */ public static int argMin(int [][]...
A network is known for its impedance value: | J = 0,15 J J = 0,11 | J = 0,15 (a) Make a Ybus value ! (b) If an express feeder is installed from bus 1 to bus 4 with a value ofj= 0.10 make a correction to the Y.bus value ! a les empresa fede is installe
Translate HLL statement given below to Assembly for (j = 0; j <= 100; j = j+1) a = a + c
Show the output, including proper spacing. for (int j = 1; j <= 4; j++) { } for (int k = 1; k <= 4; k++) { if (j <= k) System.out.print(‘*‘); else System.out.print(‘ ’); } System.out.println(); in java
Mutt's utility function is Um,j) max3m,j) and Jeffs utility function is U(m,j)-3m + j. Mutt is initially endowed with 6 units of milk and 2 units of juice and Jeff is initially endowed with 2 units of milk and 6 units of juice. If we draw an Edgeworth box with milk on the horizontal axis and juice on the vertical axis and if we measure goods for Mutt by the distance from the lower left corner of the box, then...
J 3cos (u +v+w) du dv dw. Evaluate the integral 111 J J J =L」 3 cos (u + v + w) du dv dw (Type an exact answer, using π and radicals as needed.)
] Look at the following code: for(i=1; i<=12;i++) { for(j=1;j<=(i/3); j++) { cout<<j<<" "; } cout<<endl; } Mention the output. Also put the value of i and j in each line
J-J, f(x)--3, g : S → J, g(s) = nuniber of elements in the string 's', if is even. h : J-J, h(1)- r r if is odd - . where J denotes the set of integers and S denotes the set of all character strings. Calculate each of the following if they exist (if they do not exist explain why they do not exkt): (i) fo r (i) ho f(x), 8 marks) (ii) hofo g(test)
J-J, f(x)--3, g :...
1) Compare and contrast J chain and J gene.