Question

A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under tension due to the weight of the wire. The wire is oriented at right angles to a uniform magnetic field that has a magnitude of 2.5 T and is directed into the screen of the figure. The length L of the wire is 5 cm and its mass m is 10 g. What current will produce a magnetic force on the wire that is just sufficient to remove the tension in the flexible leads, and which way is the current flowing through the wire? Current-carrying wire suspended from identical flexible leads B® magnetic field (into the screen) Ceiling I, current-carrying wire L 0.39 A, current flows left to right 0.39 A, current flows right to left 0.45 A, current flows left to right 0.45 A, current flows right to left 0.22 A, current flows left to right

Answer 1

fm I L hou groundodiona foce = magnetid forces mg -2B5L int mg 2BL 10x10 9.81 2x2.5 X 5X102 I= 0.785 Amp J= 0.39 Amp left to engent 0:39 A, flows left to right