Question

The terminal side of angle B in standard position goes through the point (- 12,7). Find the values of the six trigonometric functions of B. Give an exact answer in reduced radical form. No decimal answer will be accepted!! sin(B) = cos(B) = tan() = csc(8) sec (8) = cot(B) =

Answer 1

Given the terminal side of angle ß in standard position goes through the point (-12,7) we find the ralyos of the six trigonometric function of P Я s (-12,7) V153 x' -12 ЭХ from the triangers o AB oAtt AB" - oB² 7 (-12)+(7)" =OBt 144+49 OB 2 > 193 - From the figure SM(B) = papendicular Hypotenuse AB OB = +7 1193 boose COS(B) = - Base Hypotenusa OA OB - 13 2 1 tan (B) perpendicular AB OA Base 7 12 CSC(B) Since ) 1193 7 sec (B) = cosia COS(P) - 12/03 1193 12 Cot (B) = tancpl - X112 12 7