Question

A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under tension due to the weight of the wire. The wire is oriented at right angles to a uniform magnetic field that has a magnitude of 4.5T and is directed out of the screen of the figure. The length L of the wire is 5 cm and its mass mis 10 g. What current will produce a magnetic force on the wire such that it doubles the tension in the flexible leads, and which way is the current flowing through the wire? Current-carrying wire suspended from identical flexible leads SBO magnetic field (out of the screen) Ceiling I current-carrying wire L E 0.33 A. current flows left to right 0.33 A, current Wows right to left 0.44 A, current flows left to right 0.44 A, current flows right to left 0.67 A, current flows left to right

Answer 1

Salution OR ( aut of screen) 1 RT I ng Then is not flow When current 2T = ng 10 kg MI log g= 9.8 IT= to x g. 8 'Ta 102x9.g 0.049 ܛܲܢ >> when Tensten (T) vis dauble, Means downulard farle is increase: when current flow in the red, then I farle on rod due to regnetic field. Idfa Î (LIXB) Scanned by TapScanner

when current flow In right side then downward farle Increde. IM! -dn. WA . - 005x10m سا dfa I.( dB) df I di Blino AIB U © a 909 af SIB al f- IBL f = IX 45 X SX10? {serna strom when Tension is dauble, then current is 9T- f 220.049 = IX 4.5*54102 la 9.8* 9.8 x = FX45X5X18 I = 044 Amp Scanned by TapScanner

when current flow in rod in right side, then farce will be downward, the farce is downward then tension is dauble. 11 is Carrect. opion (C) e o 44 Amp flows left to right thank you Scanned by TapScanner