Question

A horizontal length of current-carrying wire is suspended from two identical flexible leads that are under tension due to the weight of the wire. The wire is oriented at right angles to a uniform magnetic field that has a magnitude of 4.5 T and is directed out of the screen of the figure. The length L of the wire is 5 cm and its mass m is 10 g. What current will produce a magnetic force on the wire such that it doubles the tension in the flexible leads, and which way is the current flowing through the wire?

Current-carrying wire suspended from identical flexible leads Ceiling SBO magnetic field (out of the screen) I, current-carrying wire L

possible answers:

0.33 A, current flows left to right

0.33 A, current flows right to left

0.44 A, current flows left to right

0.44 A, current flows right to left

0.67 A, current flows left to right

Answer 1

In question it is said tension must be double so magnetic force equal to weight must be down words F F = mg BID = mg mg loxloxo.8 4.5X0.05 Be I=0.4355 I=o.uya I VE Corrent must be right side 0.44A corrent flows from left to right.

Thanks for asking.

0.44 A current flow from left to right.