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Question 9 6 pts (07) Mno, will hydrolyze with water to form gaseous oxygen (O2) via...
Question 9 6 pts (27) Mno, will hydrolyze with water to form gaseous oxygen (O2) via the reaction (spontaneous as written) with E O = 0.20 V: 4Mno 7 (aq) + 2H20 (1) 4MnO2(s) + 302 (g) + 40H (aq) Calculate Ecell of this spontaneous redox reaction at 25° C under the following conditions: pH - 10 PO2 (pressure) = 0.20 atm and [MnO 2 ) = 1.0 x 10-4M Answer in 2 significant figures. 0.25 V 0.21V -0.21 V...
Question 10 Even in basic solution, MnO, can oxidize water. One product is manganese(IV) oxide. Write a balanced chemical equation for the reaction Mnog (aq) + 6H20(1) - MnO2(5) + 2H2(g) + SOH(aq) 4Mno. (aq) + 2H,0(1) --- 4MnO (5) + 302(g) + 40H (ag) 4Mno. (aq) + H20(1) - 4MnO(s) + O2(g) +2014(aq) 2MnO4 (aq) + 2H20(1) --- 2Mn?"(aq) + 302(g) + 4OH(aq) Mno," (aq) +H:0(1) --- MnO (s) +H3(e) -OH(aq)
the first picture is about some useful information, and the second picture is the question that bothers me. I wonder how we know the half-cell reaction of it. Please explain!!! TABLE 18.1 | Standard Reduction Potentials at 25°C (298 K) for Many Common Half-Reactions 8° (V) 0.40 0.34 0.27 0.22 0.20 0.16 0.00 Half-Reaction F2 + 2e →2F Ag2+ + e +Agt Co3- + e + CO2- H2O2 + 2H+ + 2e +2H20 Ce+ + e + Ce+ PbO2 +...