Question

(8) The Divergence Theorem for Flux in Space F(x, y, z) =< P, Q, R >=< xz, yz, 222 > S: Bounded by z = 4 – x² - y2 and z = 0
(8) The Divergence Theorem for Flux in Space F(x,y,z) =< P,Q,R >=< xz, yz, 222 > S: Bounded by z = 4 – x2 - y2 and z = 0 Flux
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Answer #1

F(x, y, z) = Laz, yz, 222 > 2=4 -x²_y2 +2=0. s is bounded by Z here whe the combination of Se 2=4x²_y2 Sio 2=4 – x² - y2 Sg:20 (4-422 1324 - 9u3 & F. Crux ru ) {az, yz, az?>. (241080, zu sino, u) 20$ (4_42)60072e + qu(4_uj sip?l + 2484-232 = 243 (4-V Since s is closed surface here by Divergence theorem, SS Fonds di SSS div (F) dv. where V is the volume enclosed by s = SSS2 S 2 2 SS Finds = 3 & [16+2 7 – 882] dr do =3[0]3+ S (168795-073) da 6 TT (884 - 274] [ 363 + 327 Ss Fonds 64 - 6 64 T S

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