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Use the figure below to answer the following: d. What is the direction of the force on the -2mC charge? (Answer in degrees, w
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Answer #1

Angle from x-axis, \theta = \tan^{-1} \left [\frac{F_{20 \mu C}}{F_{40 \mu C}} \right ]

\Rightarrow \theta = \tan^{-1} \left [\frac{ \frac{q_1}{r_1^2}}{ \frac{q_2}{r_2^2} } \right ]

\Rightarrow \theta = \tan^{-1} \left [\frac{ \frac{20}{3^2}}{ \frac{40}{5^2} } \right ] = 54.55^o\Rightarrow \theta = \tan^{-1} \left [\frac{ \frac{20}{3^2}}{ \frac{40}{5^2} } \right ] = 54.2^o

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