Solution
We will find ANOVA using excel
The output is given below
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Produce | 4.000 | 218.000 | 54.500 | 107.667 | ||
Milk | 5.000 | 184.000 | 36.800 | 181.700 | ||
Cereal | 4.000 | 184.000 | 46.000 | 146.667 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 701.123 | 2.000 | 350.562 | 2.353 | 0.145 | 4.103 |
Within Groups | 1489.800 | 10.000 | 148.980 | |||
Total | 2190.923 | 12.000 |
1.Null and alternative hypothesis
H1 : At least one of the mean different from others.
2. F-statistic = 2.35
3.P-value : 0.145
4. Accept H0. There is not sufficient evidence to conclude that there is no difference in the average number of pounds of bananas sold per week in three locations.
b. Since we accepting the null hypothesis and conclude that three locations have same mean therefore there is no need to perform multiple comparision test.
The accompanying data show the number of pounds of bananas sold per week at a grocery...
The accompanying data show the number of pounds of bananas sold per week at a grocery store when the banana display was positioned in the produce, milk, and cereal sections of the store. Complete parts a and b. Click here to view the banana sales data, Click here to view a table of critical values for the studentized range. a. Perform a one-way ANOVA using a = 0.05 to determine if there is a difference in the average number of...
Do we need to and If so how do we do these multiple comparison Tests? Produce Milk Cereal 63 38 27 39 20 52 61 33 54 55 56 51 37 (Milk is the one with 37 as the 5th number) The accompanying data show the number of pounds of bananas sold per week at a grocery store when the banana display was positioned in the produce, milk, and cereal sections of the store. Complete parts a and b....
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