Table 1: Experimental data for Hooke's Law lab. Mass (kg) Force (N) Ax (m) 0.100 0.100(9.8)=...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAX, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 103 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAx, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 10 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
PHY 3460 Hooke's Law and Elastic Potential Energy Questions When applying a 37.5 N force on a spring it compresses 15.0 cm. Calculate the spring 2) A spring (k 1.22 N/m) is hanging vertically. An unknown mass is hung from the spring 3) A 15.0 kg mass is hung from a spring causing it to stretch 0.25 m, find the spring constant. constant of the spring. causing it to stretch 57.3 mm. How large is the unknown mass? Then, another...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax- 2 N if it stretched or compressed, where α = 60 N/m and β 18.0 Nm2/3. The mass of the spring is negligible. (a) Calculate the work function W(x) for the spring. Let U=0 when x=0. (b) An object of mass 0.900 kg on a horizontal surface is attached to this spring. The surface provides a friction force that is dependent on distance Fr(x)2x2...
Consider a mass m suspended from a massless spring that obeys Hooke's Law (i.e. the force required to stretch or compress it is proportional to the distance stretched/compressed). The kinetic energy T of the system is mv2/2, where v is the velocity of the mass, and the potential energy V of the system is kr-/2, where k is the spring constant and x is the displacement of the mass from its gravitational equilibrium position. Using Lagrange's equations for mechanics (with...
Consider a spring of mass 1 Kg attached to a spring obeying
Hooke's Law with spring constant K
Problem 4. (15 pts) Consider a spring of mass 1 kg attached to a spring obeying Hooke's Law with spring constant k N/m. Suppose an external force F(t) = 2 cos 3t is applied to the mass, and suppose the spring experiences no damping. Suppose the spring can be displaced 0.2 m by a 1.8 N force. If the spring is stretched...
Table 1: Spring Scale Force Data Force (N) 0 Distance, x (m) ForceAverage (N) A Distance, Ax (m) Work (J) 0 0.060 0.05 0.003 0.120 0.05 0.065 0.05 0.003 0.250 0.10 0.075 0.05 0.004 0.400 0.15 0.065 0.05 0.003 0.530 0.20 0.060 0.05 0.003 0.650 0.25 Part A Post-Lab Questions: 1. Create a Force vs. Displacement (stretch distances) graph. Construct your graph on a computer program such as Microsoft Excel or Google Sheets. 2. Using the result of Analysis Question...
Suppose a force of 40 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position? c. How much work is required to stretch the spring 0.5 m from its equilibrium position? d. How much additional work is required to stretch the spring 0.1 m if it has...
Part A: A spring obeying Hooke's law has a spring constant of 1.9 N/m. If you load it with 2.2 kg (about 1 pound mass) and let Earth's gravity pull down on it, how far will it extend from its previous length? Give your answer in meters. Use 9.8 m/s2 for the acceleration of gravity. Part B: What is the velocity of a wave of any kind that has a frequency 691 Hz and a wavelength 8 meters? Give your...
Now measure the distance, x,
for two more masses and enter your measurements in the table below.
Try to estimate to the nearest 0.5 mm. Find the spring constant by
solving mg = kx for k. The spring constant is a property of the
spring so you should get nearly the same result each time.
Part 1: Spring Constant Background: A spring scale works because it obeys Hooke's Law: F=-kx. When you hang a weight, the spring stretches until the...