Question

R2 w R3 M R1 R4 » E In the following circuit, R1=0.8*4 Ohm, R2=2* 4 Ohm, R3-3* 4 Ohm, R4=2* 4 Ohm, and E= 42.1 Volt. Calculate the power Loss in R2 resistor? [Picture File-Ohm-3.jpg]

Answer 1

2 the resistance combination, R₂ and R₃ are in parallel equivalent of and R3 go the R2 these foot the R2 = 2*2=82 Rz = 3x4 = 12.2 = 16+tz R2 3+2 24 RI Rés R3 Ray ath = 4.8 2 d Ri Reg R4 Now Ri, Rég and R4 Ho are in Serties commestim, E so equivalent of them į Req Req = RitReqtR4 I = 1:6 + 4.8+ 8 = 14.42 3. current through the Rez; 1 E 42] 14.4 = 2.92 A I Req & voltage drop across Rés

o Eq = I Re Red = 2.92 x 4.8 = 14. V y current through R₂ I2 = E2 R2 14 8 = 1.75 A power loss in in R2 P2 IZ R2 = (1-75)3x8 = 24.5 Watt.