Question

QUESTION 28 1,3-bisphosphoglycerate is one of the two phosphoryl group donors in the synthesis of ATP during glycolysis, in human erythrocytes, the steady-state concentration of ATP is 2.24 mM ADP IS 0.25 mm, and 3-phosphoglycerate is 0.12 mm. Calculate the concentration of 13. bisphosphoglycerate at 25°C, assuming that the phosphoglycerate kinase reaction) is at equilibrium in the cell. (Standard delta G=-18.9). 5.3E-7M 5.1E-5M 3.4E-6 M

Answer 1

E Chemical Engineering Criven that Concentraction of ATP 2.21 mm до 0. 0.25 mm 3- phosphoglycenate 0.2 mm 298. ISK Temp. (T) Phosphoglycerate kinase Reaction cpak) is 13 - biphosphoglycerete + ADP = ATP + 3-phosphoglycorate At Equilibrium Ke Equilibrium DG" - - PT Ink Rate content K: [ATP] [ 3-phosphoglycemete] Ap] [1,3-biphosphogly ce secte] here sh=-18. 9 kJ So, - 18900 - 8.314 x 298.15 x enk We get k= 2047.95 2047.95= (2.24) (0.12) x 10-6 (0,25) X X X 70-3 x = 5.3 X 10M so, concentreton of 1,3-biphosphoglyceroute is 5.3x10 m. (2) The Glyoxylate Cycle is imporant for plants to regenerate substrates for the Hori carboxylic acid Gele.