Question

Question 19 Not yet answered Points out of 7.00 P Flag question A cylindrical conductor of radius R = 9 cm has a non-uniform current density J = 2 r12 in units of A/m2. . (a) Calculate the magnetic field at distance r = 8 cm from the center of the conductor. Select one: O a. 9720.00 T ob. 3240.00 T O c. 6826.67 T Next page

Answer 1

R = 9cm 01g. Given Cylindrical conductors of Radius with the volume curent density J= 27? using Amperies law B. de = M Jenc dé . R g & Where B is magnetic field at de = small length element s closed line integral canent enclosed by imaginary 19 Amberian loop of sadius & so J 25 g dr Sirar : (25) 2 frendo X Terc å R Tene 25 š o Ył ry = 284 afriar & Ienc = 45/8d8 ५ po 3 so B Mr Magu B 220 = so B at rer 8=8cm =0.08m B = buy ya xlox (0.08)3 2 13 The magnetic B = 3216.99 X 10 Tesla -13 field at r= 8cm (8R) is 3216.99 X10 T I None of chotion is connect) roolm field at 8=11cm magnetic (87R) R The total enclosed J2h & dr = YAO v=1483 Tout 020 (6) R chorge Tout TRY -

so B28= HRY B 258=NTRY B = M RY 28 ५ at 8=1lem zoollm B = 46 XIO *x( 9X10%) 2x Ilx102 -13 -13 of magnetic field at A Vse B = 3747.64 X10 Tesla The magnetic field at 8=11cm from from central central axis is B = 3747.64X10 Tesla. ( None of options are comert) Qir To find the direction Point P = direction of magnetic field Put thumb of Right Hand alorg cunent ( into the page! The earl finger at Point P implies the downward magnetic field So The corect option is a 8 ica d