Question

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(3) Using the Law of Sines, solve the non-right triangle where B = 5°, A = 10°, c=5

Answer 1

According to Common notation for ४ and angles in О. si des representation of sides A, the aze sebzesented in small letters with angles opposite to them capital. in C а. b 5° B ARIO c=5 in a A. Using angle angle sum property A+B+C = 180° -) 10° + 5° + c = 180° - C - 180° -15° 3) C = 165° Sine law in AABC. Applying

a C = 2 b sing Sin A sing - ). a = 5 b sin 5° sinloo sin 165° -> a & 5 - 2 b sin 5° sin 10° sin 165° sin 165° = a= 5x sinloo b= > 5x sin 5° sin 165° sin 165° a= 3.3546252 & b=1-68371966 . C-165° ał 3.3546252 bă 1.68371966
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