Question

21. The daily milk production of a new breed of cows has a standard deviation of 5 gallons. Researchers plan to sample 100 co
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Answer #1

Answer:

Given,

Mean = 0.6

Standard deviation = s/sqrt(n) = 5/sqrt(100) = 0.5

P(X < u - 0.6) = P(z < (u - 0.6 - u)/0.5)

= P(z < 0.6/5)

= P(z < 0.12)

= 0.5477584 [since from z table]

= 0.5478

Option C

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