Ayrshire cows produce an average of 57 pounds of milk per day with a standard deviation of 6 pounds. Assume the daily production is normally distributed. 20 cows are randomly selected from a herd and their day’s milk production is weighed. Let ȳ be the mean pounds of milk for this sample.
a. Find the mean and standard deviation for the sampling distribution of ȳ.
b. Use normalcdf with the sample mean ȳ to determine the probability that the mean weight of the milk produced by these cows is more than 58 pounds.
Solution :
Given that,
mean =
= 57
standard deviation =
= 6
n = 20
a)
ȳ =
= 57
ȳ =
/
n = 6 /
20 = 1.34
b) P(ȳ > 58) = 1 - P(ȳ < 58)
= 1 - P[(ȳ -
ȳ ) /
ȳ < (58 - 57) / 1.34]
= 1 - P(z < 0.75)
Using z table,
= 1 - 0.7734
= 0.2266
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