Question

8. For 0 < < 27. find all solutions of sec r = eser.

Answer 1

♡ Aniwer secue = cosecx , 0276c2R Cox xo sing => hanx=1 > x= 45°, 180+45° Lo; 0cx<25 ion:45°, 225 Hence all solutions are 45° and 225° Q:20 (9 @ simB="2 , a= 20 = sinB = 42 => B = sin (12) :: B = 30° b now, sino = b = b b= 20 sin3o = 2004/4 = 10 and i. c = Ja²b² = √20² 102 = 1053 pythagoras Hunce b= 10 theorem 4 Colors barvo tan A = 100, b=100 fan A : 100 A: freni' (100) = 89.43 Now sin A = 2/2 =) a=bsina "A

:: as 100 sin(84-48 ) = 99.99 ✓6²_a² = Vrue? 99.992 and ca 9999.000699 C: 99.995 Hence & - 99.99, C=99.995 0 T Cees is = 2/3 and 6:20 b. =) B = (65" (5/13) - 67.4 Now sing a = e = biasing - 20x sin((738) 24 E 18.46 and c = a²-b? 20?-18.46? in C: 59.23 Hence b-18.46 C: 59.23 s banx=r3 int(0,2*) ar fan' (83) - X= 60, 18° +60 = 60°,240" Hince a= 60 and 290°