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The tension member shown in Figure 1 is subjected to a tensile force T. The member has an L89x89x7.9 cross-section with 350WT a . 2 a b b b Figure 1

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Given:- 350 W Steel 89x89x7.9 (fy i sorrera fu to T - 65 ksi ~ 45ompa 42 mm 121 21 30 mm Go mm 60 Tom 60 mm t: 7.9 mm Now, aAgv gross shear = area (60+60+60+30)* 7.9 1659 mm 1559-(3-5% (22-225)*7.4) Anu = net shear curea 1044.5 mm2 Step . = 282.01589 mm L = 180 mm then, L>2w use U=0.87 Ae U Anet Ae = 0.87X703.) Ae 611-697 mm² {& Anet = Ag due to welded conne Anet. = 39x7

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