Question

1) The uniform dresser has a weight of 90 lb and rests on a tile floor for which us = 0.25. If the man pushes on it in the direction = 30° determine the smallest magnitude of force F needed to move the dresser. F Also, if the man has a weight of 150 lb, determine the smallest coefficient of static friction between his shoes and the floor so that he does not slip. Draw a complete free - body diagram (FBD) for the dresser and man each.

Answer 1

The solution for calculating smallest magnitude of force (F) to move the dresser and smallest coefficent of Static friction between his Shoes and floor so that he does not slip is given below as image file.

Free Body Fsino ton 0:25N F-0.289.Clos: 263) = 30.42116 Smallest Coefficent of static friction between his shoes and Hoor so that he Part-A- Diagram: '0=300 Table Fussoo 'N w-golb * Friction (FF) = Mg xn . now { Fx=0; Fas30° 0.25N=0.-0 Sfy 30-, N-90 - Esin30º = 0 F60.866) -0.25N=0- N-F C0.5): 90 F -0.25 (N) 0:289N 0.866. N-0289 (05) 3 90.7 - 90 0.855 N=10526315. Answer f= 30.42116 part-B : does not slip

w 1501b F ws 300 2011 Esingo Finan Nman pemant x Niman 30.12tlcos:300) Ź Fx D => Finan Fman = 26-34875] < Fy=1 Niman - 150+ 30.421 (sin 30°) = 0 Nman = 134.78916 Himani Fman - Mman x Nman 26 344 137.789 leman =0.195 Answer