Question

Question 1 a) Calculate the Effective Resistance of the circuit and total current of the network in figure 1 (5 marks) b) Calculate the Effective Resistance of the Network of Resistors in figure 2 (5 marks) Total 10 marks Space to answer Question 1 here + 9 V - R 90 12 R2 45 12 SR 180 12 Figure 1: 122 122 102 102 A $20 202 222 122 B Figure 2

Answer 1

Answer Question 1 a I Given, v=gv Ri=902 R2 = 452 R3 = 1802 as, the resistors are in parallel connection so, equivatant resistance of the circuit, I+I+ Ri R₂ R3 R => R= R=( + 1805 2 45 RE R = 25.71 2 so effective resistance, R=25.712 And, the total current of the networt is I = I = A 25.71 I = 0.35 A Ans,

6 RI RI w RU d Aww mung an R2 R2 R2 B h Given, R=A2 R₂ = 22 equivalant resistance between c and f is Ref = (R+R) 11 R₂ → Ref = (1+1) 11 2 de Rest R 211 2 2x2 2+2 Again, equivalant resistance between b and g is Rbg (Rit + Ref) 1 R2 R bg = (1+1) 11 22 =) Rog= 2X2 Rog Smilovily, equivalant resistance between the Point, a and his, Ran= 152

Therefore, equivaland susistance between the A and B is R = RA R + Ran * R = (141) 2 ) R = 22 So, effective resistance of the network is [R=22