Question

Question 10 (1 point) [JCUSRDFATK] Find the effective (total) resistance for the H.A.L. circuit below. R1 - 1250 R2 = 1.2 kg R3 = 605 RT = R3 R2 R. | V,

Answer 1

Solution:

Given that: R₁ = 125 Ohms; R₂ = 1200 Ohms and R₃ = 605 Ohms

The equivalent resistance of resistances R₁ and R₂ is given by

$\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$

or $R= (\frac{125\times1200 }{125+1200})$

or   $R= 113.21 \Omega$

Now R and R₃ will be in series. Then, the total resistance for given circuit is given by

R_T = R + R₃

or R_T = 113.21Ω + 605Ω

or R_T = 718.21Ω