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The scores on the SAT verbal test in recent years follow approximately the normal distribution distribution. Students get a m
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P (4002 400< X < 550 5o) = P(Z <0.06)-P (24.1.2 - 05636- [H (22) [1-0.8888 = 0.5636- = 0.5636- 0.12 0.4524 Therefore the prop550-533 (c) To find the proposition of students seating over 550 P(x>550) = P(2> 17) -P (27016) 1-1/2cool 6) - - 0.5636 overX-533 = 1.282-०१ 9 2-533 139.138 = 139.738+533 X= 612.7 X= 673 X=673

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