Find the solution fort in the equation 5(21)=4. O t= -0.322 Ot=0.861 O t= -0.861 Ot=0.322
Solve fort, 0 < t < 27. 32 sin(t)cos(t) = 12 sin(t)
In the equation B = - .013t+ 0.025N, solve fort if B = .04 and N = 3. Answer: t = (Round to two decimal places.) Show Answer 2.69 Question 3: N/A out of 2 in 0 attempt(s) In the equation B - .013t+ 0.025N, solve for N if B = .05 and t = 2. (Round to two decimal places.) Answer: N Show Answer Question 4: N/A out of 2 in 0 attempt(s) 2- In the equation 2 =...
Suppose the time constant is 400 ms, determine v (t) fort >0. t = 0 10 k92 24 v ☺ 4 kN vn+ 40 4F 1.71e-3.8t volts 2.38e-5.3t volts 6.85e-2.5t volts O 14e-5.3t volts None of the above
Problem 2: For the circuit shown below, find the following: The expression of i(t) fort > 0. The voltage vc (t) fort > 0 Calculate the peak energy stored in the capacitor Calculate the real power dissipated in the load formed by R and C. b) d) 40 UF + 0 -V-24 Ve0 400 Hz
Solve the heat flow problem: ot (x, t) au au (x, t) = 2 (x, t), 0 < x <1, t > 0, a x2 uz(0,t) = uz(1, t) = 0, t> 0, u(a,0) = 1 + 3 cos(TTX) – 2 cos(31x), 0<x< 1.
1) For the circuit below, a) Find i(t) fort > 0 b) Find vu(t) fort > 0 [you can do this by using your answer to part a) and the relationship between voltage across an inductor and current through an inductor] c) Plot your answers to parts a) and b) on separate plots. I lists to V. (4) 2H 2) For the circuit below, if the capacitor is fully discharged for t < 0, a) Find i(t) fort 0 you...
Solve the BVP: от от OT PDE: BC: T(0.t) = (5,0) = 0 (5.1) = 0 0SX 55 Or? BC: TO and T(x,0) = 1-X
please solve number 5 only #4 Find i(t) fort <0 and > 0 for the following circuit (pts. 20) 1 = 0 40 Ω 30 Ω 20 V 3F: ΤΣ 0.5i 50 Ω #5. Determine vc, le and energy stored in the Capacitor and inductor in the following circuit under DC condition. 8 Ω (pts. 20) + Τι c 2F 10A 4Ω ele 0.5 Η 5Ω
(1 point) Solve the initial value problem 13(t+1) 94 – 9y = 36t, fort > -1 with y(0) = 10. Put the problem in standard form. Then find the integrating factor, p(t) = and finally find y(t) = 1