Suppose the time constant is 400 ms, determine v (t) fort >0. t = 0 10...
1. Find v(t) fort> 0 in the circuit in below: t=0 222 w 622 w + 10V 2 F +1 50 V Assume the switch has been open for a long time and is closed at t=0.
Find v(t) for t> 0 in the given circuit. Assume / = 4u(t) A. t=0 1H mo of + 4.5 A ( 102 4F 522 DI - The value of v(t) = [A + (B)ect + (D)e-4.949tju(t) V where A = B = CE and D =
Solve for I.(t) fort >0 as the switch moves from 20 V voltage source to 150 mA current source for t>0. t=0 R=2000 IL R2 Vs1 20V 10uF 100 L (1/4.1) H 150 mA
5. Determine v(t) for t < 0 and t > 0 in the circuit shown 0.5 H 0 3? 8? 4i0 24 V (+ 20v
4. Find the voltage v(t) fort > 0 in the circuit shown below. (25 points) 20022 0.4 H 40 v t=0 X 2002 20 pFv
In the circuit given below, V = 28 V. Find it for t> 0. 32 1 H iſt) 40u(t) A 192 V 40 mF O 10 = [8.729 sin(4.5830e-29410) A O 10 = [218.232 cos(4.5831)e-2940 A it = [218.232 sin(4.5831e-2]40) A O 10 = [8.729 COS(4.583 18-2010 A
In the linear time-invariant circuit below. Before time t the voltages across the capacitors are v 1V, and v-4V. The switch is closed at time t 0 and remains in this condition for a time interval of t = 2π. The switch is opened at t = 2T, and remains open thereafter. What are the values of v1 and v2 for t > 2π? 9. 0 the switch is open, and t-2π L=2H t=0 V2 C1 = C2 = 4F
Obtain v(t) for t> 0 in the given circuit. Assume v;= 110 V. F1 F 102 TE The value of v(t) = A cos (Bt + Cu(t) V where A = BOV and C =
Find v for t>O if the circuit is under de condition at t=0-. t = 0 w 16 Ω 82 + 242 1/36 F + + 20V 8V Annor.
Find i(t) for t> 0 in the given circuit. Assume v;= 34 V. t=0 10 22 6022 [i(t) 1 mF Vi + 40 Ω 2.5 H O (0) = –10.88te-20+ (0) A i(t) = -27.20 te-20tu(t) A i(t) = 13.60te-20tu() A O i(t) = –17.00 te-20t4() A