Use basics of circuits.
Detailed solution is given below:
Obtain v(t) for t> 0 in the given circuit. Assume v;= 110 V. F1 F 102...
Calculate i(t) for t> 0 in the given circuit. Assume A = 35[1 – u(t)] V. + V - 1 F 16 A +1 H 592 The value of i(t) = (A) cos (Ct + Dº)u(t) A where A = C= and D =
Find v(t) for t> 0 in the given circuit. Assume / = 4u(t) A. t=0 1H mo of + 4.5 A ( 102 4F 522 DI - The value of v(t) = [A + (B)ect + (D)e-4.949tju(t) V where A = B = CE and D =
Find i(t) for t> 0 in the given circuit. Assume v;= 34 V. t=0 10 22 6022 [i(t) 1 mF Vi + 40 Ω 2.5 H O (0) = –10.88te-20+ (0) A i(t) = -27.20 te-20tu(t) A i(t) = 13.60te-20tu() A O i(t) = –17.00 te-20t4() A
In the given circuit, identify (0) and i(t) for t> 0. Assume 10) = 0 V and 1(O) = 2.50 A. + 5u(t) A 222 v+0.5 F ell 1 H [3.780 e-t2cos(1.3229t - 90°)]u(1) V [5 + 2.67252 e-t2cos(1.3229t - 200.79] A [0 – 2.67252e-t2cos(1.3229t – 200.7°)] A [5 – 2.67252e-t/2 cos(1.3229t+ 200.79] A [2.673e-t2cos(1.3229t – 90°)]u(0) V [1.336e-t2 cos(1.3229t+ 90°)]/(t) v
Given the circuit in Figure 8.6, find vc(t) for all t>0. t=0 102 20 V * vc(t) 1/10 F 10H Figure 8.6
In the circuit given below, V = 28 V. Find it for t> 0. 32 1 H iſt) 40u(t) A 192 V 40 mF O 10 = [8.729 sin(4.5830e-29410) A O 10 = [218.232 cos(4.5831)e-2940 A it = [218.232 sin(4.5831e-2]40) A O 10 = [8.729 COS(4.583 18-2010 A
Question 4 Find i(t) for t >0 for the circuit below. 4Ω 12 V 5 H 3 A
Find v for t>O if the circuit is under de condition at t=0-. t = 0 w 16 Ω 82 + 242 1/36 F + + 20V 8V Annor.
5. Determine v(t) for t < 0 and t > 0 in the circuit shown 0.5 H 0 3? 8? 4i0 24 V (+ 20v
(2) The circuit is at steady state for t<0. Find v(t) for t>0. Answer t=0 ZF Navt)14 T