Question

In the circuit given below, V = 28 V. Find it for t> 0. 32 1 H iſt) 40u(t) A 192 V 40 mF O 10 = [8.729 sin(4.5830e-29410) A O 10 = [218.232 cos(4.5831)e-2940 A it = [218.232 sin(4.5831e-2]40) A O 10 = [8.729 COS(4.583 18-2010 A

Answer 1

tho 40 ult)=0 » Curret soune is opened. In steady state Illo) هد | 28V for to shortel & C is Velo) opened Izlo)= oA Velol=28V txo SL= s - sc In Laplec domain for too I becach c becaus s'hom = 25 Saare Cores de series with c & take Velo) 28 4oulth = A voltage 28 s s 283 28 40 s 32 S I Ils) I = 40 - I (s) 28 LO 1 SIR + th 25 writing loop equation 28 I - 29 - + Ils) + +(3+5)I(s) = 0 + Ils) + 25 I (s) + (3 ts) I (s)=0 -40

40 40 s I() [ 2s + S +4 3.0 slots us - 40 S I(s) = 40 s²+45+25 40 (5+2)²+ +21 = (ف)L 4o 40 Jai 8.728 x 4.582 (5+2)+(521)2 Jai (5+2)² + (W21)² Ils) (3+2)² + (4:58283 Applying Iverse Laplace gives i(t) = [8.728 "Sin 4:582 t] ult) A option is correct. -27
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