(1 point)
If Vs(t)=91e^(−42t)mV and is(0)= -5 mA, find is(t) for
t>0
is(t) = mA
8 mF 20 mH 24 mF
Find i(t) for t> 0 in the given circuit. Assume v;= 34 V. t=0 10 22 6022 [i(t) 1 mF Vi + 40 Ω 2.5 H O (0) = –10.88te-20+ (0) A i(t) = -27.20 te-20tu(t) A i(t) = 13.60te-20tu() A O i(t) = –17.00 te-20t4() A
= For the circuit of Fig. 8.27, let io(t < 0) = -1 mA, 1,(t > 0) = 2 mA, R 2.000 Q, R = 3,000 12, and L = 20 mH. a. Find va for t > 0. b. What is the approximate duration of the transient? 6. Sketch va(t). FIGURE 8.27
Find i(t) for t>0 for the circuit in Fig. 16.37 Assume i(t)- [6(t) + 35(t)]mA 16.14 1Ω i(t) ist) ( 0.2 H 2Ω
Find vo(t) for t > 0 Q#3 and
Q#4
3. Find vo(t) for t0 4 H 2Ω 4Ω 4 A Answer: vo(t)4e2t [At 0 4. Find i(t) for t> 0 5 mA 1 mH Answer: it) -5e7.5*10°1 [mA] t20
In the circuit given below, V = 28 V. Find it for t> 0. 32 1 H iſt) 40u(t) A 192 V 40 mF O 10 = [8.729 sin(4.5830e-29410) A O 10 = [218.232 cos(4.5831)e-2940 A it = [218.232 sin(4.5831e-2]40) A O 10 = [8.729 COS(4.583 18-2010 A
5. Determine v(t) for t < 0 and t > 0 in the circuit shown 0.5 H 0 3? 8? 4i0 24 V (+ 20v
5. ??? v. (0) = 20Y ?? v, v * ??? i ?????? t> 0
5. Let v(0) 20V. Find vov and i, for t>o 8? 5? 20.5FC Figure.5
Solve for Iz(t) in the circuit shown for t>O as the switch is closed for t>0. t=0 R3=2000 Rz=2000 Ix V. 24V R; 2009 R2 1000 30 mH
Solve for Vc(t) for t> 0 as the switch (SW1) becomes opened and the switch (SW2) becomes closed for t>O. t=0 20 mH t=0 R2=160 SW1 SW2 Vs + 80V R, 240 VC с (1/600) F R3 8Ω (4).4 1.5 A