Homework Answers
In the circuit given below, V = 28 V. Find it for t> 0. 32 1...
In the circuit given below, V = 28 V. Find it for t> 0. 32 1 H iſt) 40u(t) A 192 V 40 mF O 10 = [8.729 sin(4.5830e-29410) A O 10 = [218.232 cos(4.5831)e-2940 A it = [218.232 sin(4.5831e-2]40) A O 10 = [8.729 COS(4.583 18-2010 A
Find i(t) for t> 0 in the given circuit. Assume v;= 34 V. t=0 10 22...
Find i(t) for t> 0 in the given circuit. Assume v;= 34 V. t=0 10 22 6022 [i(t) 1 mF Vi + 40 Ω 2.5 H O (0) = –10.88te-20+ (0) A i(t) = -27.20 te-20tu(t) A i(t) = 13.60te-20tu() A O i(t) = –17.00 te-20t4() A
For the circuit above, vS(t) = 120 cos(20t+45°) V, R = 100 Ω, L = 5...
For the circuit above, vS(t) = 120
cos(20t+45°) V, R = 100 Ω, L = 5 H,
C = 5 mF.
Find vO(t).
www. visco) 1 c+vol)
In the circuit shown, v(t) = -800 cos(1000t + 130°)V i(t) = V2 cos(2000t + 45°)A...
In the circuit shown, v(t) = -800 cos(1000t + 130°)V i(t) = V2 cos(2000t + 45°)A Note that the sources have different frequencies. Determine the values of R and C such that va(t) = –1500 sin (20000 V R w valt) 3000Q () i(t) v(t)
P4.67 Solve for i(t) for t > 0 in the circuit of Figure P4.67 with R-500....
P4.67 Solve for i(t) for t > 0 in the circuit of Figure P4.67 with R-500. given that i(0+) 0 and v(0+) 20 V. [Hint: Try a particular solution of the form (1) = A cos(100r) B sin(100r).] t=0 I H 20 sin(1001) i(t) It(r) 100 ?F Figure P4.67
In the given circuit, identify (0) and i(t) for t> 0. Assume 10) = 0 V...
In the given circuit, identify (0) and i(t) for t> 0. Assume 10) = 0 V and 1(O) = 2.50 A. + 5u(t) A 222 v+0.5 F ell 1 H [3.780 e-t2cos(1.3229t - 90°)]u(1) V [5 + 2.67252 e-t2cos(1.3229t - 200.79] A [0 – 2.67252e-t2cos(1.3229t – 200.7°)] A [5 – 2.67252e-t/2 cos(1.3229t+ 200.79] A [2.673e-t2cos(1.3229t – 90°)]u(0) V [1.336e-t2 cos(1.3229t+ 90°)]/(t) v
Calculate vo(t) in the circuit shown in the figure below if i(t) is 200 cos(105t+ 60°) mA, i2(t) is 100 sin(105t90°) mA, and vst) 10 sin(105t) v uci) + 250 nF o(r) 52 Ohm Calculate vo(t) in the...
Calculate vo(t) in the circuit shown in the figure below if i(t) is 200 cos(105t+ 60°) mA, i2(t) is 100 sin(105t90°) mA, and vst) 10 sin(105t) v uci) + 250 nF o(r) 52 Ohm
Calculate vo(t) in the circuit shown in the figure below if i(t) is 200 cos(105t+ 60°) mA, i2(t) is 100 sin(105t90°) mA, and vst) 10 sin(105t) v uci) + 250 nF o(r) 52 Ohm
6.3 Exercises In Exercises 1-5 find the current in the RLC circuit, assuming that E(t) =...
6.3 Exercises In Exercises 1-5 find the current in the RLC circuit, assuming that E(t) = 0 fort > 0. 1. R = 3 ohms; L = 1 henrysC = .01 farads; Q. = 0 coulombs, 10 = 2 amperes. 11. Show that if E(t) = U coswt +V sin wt where U and V are constants then the steady state current in the RLC circuit shown in Figure 6.3.1 is w?RE(t) + (1/C - Lw?) E' (t) I where...
Q4. Find the Norton's equivalent circuit with respect to the terminals a and b, and write...
Q4. Find the Norton's equivalent circuit with respect to the terminals a and b, and write the answer in polar form. 20 | | 11/30°A 1 40 403 200 4240° v bom 32 22-20°v Q5. Find i(t) in the network. (t) 22 AM 1s(t) = 4 sin(2kt) A 0 4mH3 = 3 mF vs(t) = 10 cos(2kt+30°) V 422 Q6. Find the i(t). 212 is(t) = 10 sin(1kt + 10) A W ΔΩ ans I. 2 mF vs(t) = 10...
Calculate i(t) for t> 0 in the given circuit. Assume A = 35[1 – u(t)] V....
Calculate i(t) for t> 0 in the given circuit. Assume A = 35[1 – u(t)] V. + V - 1 F 16 A +1 H 592 The value of i(t) = (A) cos (Ct + Dº)u(t) A where A = C= and D =
In the circuit given below, V = 28 V. Find it for t> 0. 32 1 H iſt) 40u(t) A 192 V 40 mF O 10 = [8.729 sin(4.5830e-29410) A O 10 = [218.232 cos(4.5831)e-2940 A it = [218.232 sin(4.5831e-2]40) A O 10 = [8.729 COS(4.583 18-2010 A
Find i(t) for t> 0 in the given circuit. Assume v;= 34 V. t=0 10 22 6022 [i(t) 1 mF Vi + 40 Ω 2.5 H O (0) = –10.88te-20+ (0) A i(t) = -27.20 te-20tu(t) A i(t) = 13.60te-20tu() A O i(t) = –17.00 te-20t4() A
For the circuit above, vS(t) = 120
cos(20t+45°) V, R = 100 Ω, L = 5 H,
C = 5 mF.
Find vO(t).
www. visco) 1 c+vol)
In the circuit shown, v(t) = -800 cos(1000t + 130°)V i(t) = V2 cos(2000t + 45°)A Note that the sources have different frequencies. Determine the values of R and C such that va(t) = –1500 sin (20000 V R w valt) 3000Q () i(t) v(t)
P4.67 Solve for i(t) for t > 0 in the circuit of Figure P4.67 with R-500. given that i(0+) 0 and v(0+) 20 V. [Hint: Try a particular solution of the form (1) = A cos(100r) B sin(100r).] t=0 I H 20 sin(1001) i(t) It(r) 100 ?F Figure P4.67
In the given circuit, identify (0) and i(t) for t> 0. Assume 10) = 0 V and 1(O) = 2.50 A. + 5u(t) A 222 v+0.5 F ell 1 H [3.780 e-t2cos(1.3229t - 90°)]u(1) V [5 + 2.67252 e-t2cos(1.3229t - 200.79] A [0 – 2.67252e-t2cos(1.3229t – 200.7°)] A [5 – 2.67252e-t/2 cos(1.3229t+ 200.79] A [2.673e-t2cos(1.3229t – 90°)]u(0) V [1.336e-t2 cos(1.3229t+ 90°)]/(t) v
Calculate vo(t) in the circuit shown in the figure below if i(t) is 200 cos(105t+ 60°) mA, i2(t) is 100 sin(105t90°) mA, and vst) 10 sin(105t) v uci) + 250 nF o(r) 52 Ohm
Calculate vo(t) in the circuit shown in the figure below if i(t) is 200 cos(105t+ 60°) mA, i2(t) is 100 sin(105t90°) mA, and vst) 10 sin(105t) v uci) + 250 nF o(r) 52 Ohm
6.3 Exercises In Exercises 1-5 find the current in the RLC circuit, assuming that E(t) = 0 fort > 0. 1. R = 3 ohms; L = 1 henrysC = .01 farads; Q. = 0 coulombs, 10 = 2 amperes. 11. Show that if E(t) = U coswt +V sin wt where U and V are constants then the steady state current in the RLC circuit shown in Figure 6.3.1 is w?RE(t) + (1/C - Lw?) E' (t) I where...
Q4. Find the Norton's equivalent circuit with respect to the terminals a and b, and write the answer in polar form. 20 | | 11/30°A 1 40 403 200 4240° v bom 32 22-20°v Q5. Find i(t) in the network. (t) 22 AM 1s(t) = 4 sin(2kt) A 0 4mH3 = 3 mF vs(t) = 10 cos(2kt+30°) V 422 Q6. Find the i(t). 212 is(t) = 10 sin(1kt + 10) A W ΔΩ ans I. 2 mF vs(t) = 10...
Calculate i(t) for t> 0 in the given circuit. Assume A = 35[1 – u(t)] V. + V - 1 F 16 A +1 H 592 The value of i(t) = (A) cos (Ct + Dº)u(t) A where A = C= and D =
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