Question

Bob is standing on a bridge over the Credit River. He throws a 0.0830-kg rock straight down with a speed of 10.51 m/s. The rock hits the water 1.47 s later. What was the height of the rock above the water in metres at the moment it was thrown? Enter the magnitude ONLY no SIGN. Enter your final answer up to 5 decimal places. Do not enter units.

Answer 1

on a Qu Bob is standing bridge over the Credit River. He thorous a 0.0830 kg sock Straight down with a speed of 10.51 m/s. The rock hits the water 1.47 second later what was the height of the stock above the water in meters at the moment it thrown? solution Using Law of motion S = ut + 10,51 x 1.47 + 1x9.8 x WAS tat { *9.8*(1.47) 15.4497 + 10, 58841 26.03811 Answer Height = 5 = and #= l. 47 second Given – Initial velocity u = 10.51 m/s acceleration : a = 9.80 m/s

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