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The cells are suspended in a medium at a concentration of 10 cells per mL: if...

The cells are suspended in a medium at a concentration of 10 cells per mL: if an aliquot of 1 mL is withdrawn, how would you calculate the probability that exactly 8 particles are observed?

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Answer #1

Answer;

Given,

\lambda = 10

Poisson distribution P(X) = e^-\lambda*\lambda^x/x!

P(X = 8) = e^-10*10^8/8!

[here n! = n(n-1)(n-2)*.........1!]

= e^-10*10^8/(8*7*6*5*4*3*2*1)

= 0.1126

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