Question

A uniform plank of mass m and length L is connected to a wall by a wire of mass mw attached to the plank at L/3 as shown. The wire is perpendicular to the wall. The plank rests on the junction of the floor and wall at an angle as shown. A wave with amplitude A and wavelength A propagates along the wire. Disregard reflections. 1/3 e A. (5 points) Draw an extended free-body diagram of the plank. B. (20 points) Find the maximum speed of a particle in the wire. C. (5 points) Calculate the maximum displacement of a particle in the wire, assuming that its maximum speed is 76 m/s, the mass of the plank is 1.3 kg, the mass of the wire is 0.00025 kg, the length of the rod is 0.86 m, the wavelength is 0.28 m and the angle is 52º.

Answer 1

classmate Date Page solli- رسا FBD Tension in wire Acadl 3 A mg = 21 3 Ax Ay Atequilibrium EMA = 0 mex I sine -Jxzę code 7 Io 3ng tan o 4 Tension in wire Tensim in wire maximum speed in wire Vmax ² T v me & mass per Unit Tength of wire

Date Page mass of wire = mes mo - longth of wire length of wire = 2l sino 3 C me mw sino 3mio al sino i Vmax T zmy tano me 4 3 mo 2d sino Nmax = mgltandosino 2 mW Auswer

Vmax = 78 m/s t = 0.28 m o=528 mo o 0.00028 kg m = 103 kg l=0.86 m Veft 78 -- f- Vmay 1 HZ De 28 F = 278.5714 Hz Aisa V me nge derno, sino may 2mo - f Amox mgd tano sino 2 mo maximum displacement +1+349-34*0.86xtem 52 pins 278.5714 x mayo 2 x0.00028 Amay 0.50452 m Answer