Question

Determine the acceleration of the box after it is released. m1. A box (mass m = 20 kg) is placed on a slope (LaTeX: \thetaθ = 40°), as shown in the diagram below. The coefficients of friction between the box and the slope are LaTeX: \muμs = 0.6 and LaTeX: \muμk = 0.4. The box is released from rest on the slope.

Determine the acceleration of the box after it is released.

2.A diving board has length of 1.8 m and a total mass of 65 kg. However, the mass is not uniformly distributed, so its center of mass is off center as shown in the diagram below. However, we know that the moment of inertia around the center of mass is 20 kg m2. The board is fixed to rotate around its far left end. A support pushes up with a force of 750 N at the midpoint of the board at the angle shown. A boy steps on the far right end of the board, exerting a downward force of 500 N. What is the magnitude of the board's angular acceleration at the moment the boy first steps onto it

3. A string in a piano is tuned to emit sound with a fundamental frequency of "f" by adjusting the tension to be Ts. Which of the following modifications would give a fundamental frequency of 3f

4.A string under tension carries a transverse wave traveling at a speed LaTeX: \upsilonυ. If the tension in the string is doubled, what will be the speed of a transverse wave traveling down the string

5.A simple pendulum completes one oscillation in 1.0 second. If the length and the mass of the pendulum are both doubled, how long will it take the pendulum to make one oscillation

6. A sine or cosine wave is travelling in air. The difference between the minimum separation of any two particles on the wave always having the same speed and the same velocity i.e.

|separation of 2 particles with same speed - separation of 2 particles with same velocity|

7. The sound intensity level of a dog’s bark is 40 dB. The intensity of a rock concert is 10,00 times that of the dog’s bark. What is the sound intensity level of the rock concert

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Answer #1

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Solutions 1 m=2011g o=you frossen coussu my lesa 0.6 Mk= 0.4 When box mo slides then kinetic friction acts on the box. From F

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