Let X be the number of time computer crashes
So X ~ Poisson (6) every 24 hours
X ~ Poisson (6/24) every hour
i.e. X~ Poisson ( 0.25) every hour
If we consider the 5-hour timeframe
X~Poisson( 5*0.25) in 5 hour
i.e. X~Poisson( 1.25) in 5 hour
Required probability
= P(X =0 ) in 5 hours
Answer: 0.2865
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