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The formation of nitrous acid occurs as shown below: 202(g) + N2 (g) + H2(g) 2...
1. From the following equations and enthalpies, determine the molar heat of formation of HNO2(aq) . NH4NO2(aq) → N2(g) + 2H2O(l) ∆H = -320.1 kJ NH3(aq) + HNO2(aq) → NH4NO2(aq) ∆H = -37.7 kJ 2NH3(aq) → N2(g) + 3H2(g) ∆H = +169.9 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆H = -285.8 kJ
Hess's Law (b) Given the following thermochemical data: 2HNO3(aq) +A920(s) - H2O(1) +2AgNO3(aq) AH = -44.8 kJ Ag20(s) - 2Ag(s) + 1/2O2(9) AH = 31.0 kj H20(1) - H2(9)+1/202(9) AH = 285.8 kJ Use Hess's Law to determine AH for the reaction: Ag(s)+HNO3(aq) → 12H2(9)+AgNO3(aq) AH =
11 12 13 Combustion of glucose occurs as shown below: 2C6H12O6 (s) + 12 02 (9) 12 H20 (1) + 12 CO2 (9) Apply Hess' law and calculate the AH for the above reaction. Useful thermochemical data are given below. Just type the final numerical answer with proper sign and sig figs. C (s, graphite) + O2 (9) - CO2 (9) AH = -393.50 kJ H2O (9) H2(g) + 1/2 02 (9) AH = +241.82 kJ H20 (0) - H20...
1. Calculate AH for the reaction C2H4 (8) + H2() → C2H6), from the following data. C2H4 (g) + 3 02 (®) → 2 CO2 (s) + 2 H20 (1) C2H6 (g) + 7/2 02(g) → 2 CO2(g) + 3 H20 (1) H2 + 1/2O2() → H20 (1) AH = -1411. kJ/mole AH = -1560. kJ/mole AH = -285.8 kJ/mole 2. Calculate AH for the reaction 4 NH3(g) +502 (g) → 4 NO(g) + 6 H20 (g), from the following...
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
6. Use the following thermochemical equation for the synthesis of ammonia N2(g) + 3 H2(g) → 2 NH3(g) AH = -91.8 kJ Rewrite the thermochemical equation to show 3 moles of hydrogen being produced? Rewrite the thermochemical equation to show 6 moles of hydrogen being produced? Rewrite the thermochemical equation to show the production of 6 moles of NH3 produced? 7. Use the thermochemical equation below to find the AH of the following: CH_(g) + H2O(g) → CO(g) + 3...
3. Use the thermochemical equations shown below to determine the enthalpy for the final reaction: N2(e) +202(g) → 2NOz (6) AH = ? Using (1) Nz (€) + 3H2(E) → 2NH3(g) AH = -92.2 kJ (2) 2NH, (g) + 4H20 (1) ► 2NO2 (g) + 7H2(g) AH = 1301.8 kJ (3) 2H20 (1) ► 2H2(g) + O2(g) AH = 571.6 kJ
Which of the following statements is false concerning the reaction of hydrogen gas and oxygen gas given below? H2(g)+1/2O2(g)>H2O Which of the following statements is false concerning the reaction of hydrogen gas and oxygen gas given below? H2(g) +029) - H20(1; AH = -285.8 kJ Select one: a. For the reaction H2(g) + O2(g) - H2O(g), AH is not equal to -285 b. If the equation is reversed, AH becomes +285.8 kJ. If the equation is multiplied by 2, AH...
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data
2. Use the thermochemical equations shown below to determine the enthalpy for the final reaction: Nz (e) + 2O2 (g) → N204 (g) AH = ? Using: (1) 2NO2(g) → N2 (g) +202 (8) AH = -66.4 kJ (2) N2O. (g) → 2NO, (e) AH = 57.2 kJ