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QUESTION 5 Given is a CPM project network diagram as shown below. А C F Start E Н. End B D G A B D E F G H Activity day Start

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a) The project will flow from and get completed along either the path A-C-F-H or A-C-E-G-H or B-D-G-H.

Now time along A-C-F-H = 6 + 8 + 9 +6 = 29 days

Time along A-C-E-G-H = 6 + 8 + 4 + 4 + 6 = 28 days

Time along B-D-G-H = 3 + 7 + 4 + 6 = 20 days.

Since the longest time is along A-C-F-H, it is the critical path and the project completion time is 29 days.

b) Earliest start time of activity G = maximum of (earliest finish of E or D).

Now, earliest finish of activity E = 6 + 8 + 4 = 18 days

And, earliest finish of activity D = 3 + 7 = 10 days

Hence, Earliest start time, ES of activity G = 18 days

c) Latest finish of activity C = minimum of (latest start of E or F).

Now latest start of F = Project completion time - Duration of activity H - Duration of activity F

= 29 - 6 - 9 = 14 days

And, latest start of E = Project completion time - Duration of activity H - Duration of activity G - Duration of activity E

= 29 - 6 - 4 - 4 = 15 days

Hence, Latest finish time, LF of activity C = 14 days

d) The critical activities are ACFH, along the critical path.

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