Question

k=300

BRO p=2800 kg are m3 Aluminum Heat sinks of rectangular profile (k = 290 W m-K c = 900 kg-K commonly used to remove heat from a surface whose temperature is Ts = 150°C. The temperature of the surrounding air is 20°C. The natural heat transfer coefficient associated with the surrounding air is h = 200 m2-K Determine the temperature distribution along a fin. W Alr Toogh 20 mm 3 5 150°C 90 mm Assumption: Steady State, Two-Dimensional Conduction Constant Properties

Answer 1

ANSWER PA461 27 GWEN DATA = 290 wlmb c = 900 J llegr S - 2800 kg/m3 200 wlm? K. 2. 4 6 soc Tomm - Now theat loss from tip of fim is given with hp KA 2012 (0.09 +004) 290 X 0.09 0.01 1.06 Now for me = 7.06x0.09 -0.61 & tence of finis finding the temperature distribution insulated tip ir hasing Ta To Cosh n (1-x) C Tenperature distribution то-то Cashme

distribution now RAUE? charges Therefore temperature T-20 cash 70.600.09.8) Cos (0.63) 150 - 107.9 (0.63 - 7.061) - Temperature distribution of tin is having connective head loss from the tip of firem m(lead) Cashme iie Cosh m To -TA 2) L+AL 0.104 were AL Ac 0:09 *OOY Р 210.09 +0.04) - 0.014 So for T-20 Cash (to6 (0.014) 15-20 Cash (7.06 X0-104) T-20 cosh (0-733 - 7069) 130 1.28 Now T-20 = 101.4 cosh (0-733 – 7.061) mi for a tingular temperature expert ñia Ta similarly mata he CA please upvote its reenary k CS