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(7 points) 8. A tank initially contains 80 L of a solution in which 20 g of salt is dissolved. A solution with a salt concent
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y Yo = 20 cogm. egkez 54m be amount of salt at t 80L 209 then dy = (Rate in) - (Rate out) dt ta 3 min. pate in z 5x2= 10 g/m5 Y= 2 :( 80+24)+ < ( 80+2+)-) tzo Yo = 20gm at 20 = 2 (80) + C (80)-3/2 > CE - 140 (80)/ Hence y = E2 (80+2+) + [ -190 (80)3

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