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0 Assume that a simple random sample has been selected from anomaly distributed population and to the given claim. Identify t
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Answer #1

Given

n = 34                      ( sample of 34 coins are collected )

\bar{x} = 2.49507             ( sample coins have mean weight of 2.49507 g )

s = 0.01277              ( sample standard deviation is 0.01277 g )

To Test :-

H0 : \mu = 2.5            ( sample coins come from a population with a mean weight of 2.5 g )

H1 : \mu \neq 2.5         ( sample coins may not come from a population with a mean weight of 2.5g )

{ Note that all options patterns are not visible in given image , so can't determine which option have correct above pattern }

Test statistics :-

TS = \frac{\bar{x}-\mu}{s/\sqrt{n}}

     = \frac{2.49507-2.5}{0.01277 /\sqrt{34}}

TS = -2.251104

Hence , calculated test statistics value is TS = -2.251

To find critical value :-

Since alternative hypothesis is of "\neq" type , so these is two-taile t-test,and thus t-critical value will be given by tala

Here tala is t-distributed with n-1 = 34-1 = 33 degree of freedom and 1596139398099_blob.png =0.05,

It can be computed from statistical book or more accurately from any software like R,Excel

From R

> qt(1-0.05/2,df=33)
[1] 2.034515

Thus tala = 2.035

The critical value is 2.034

Rejection criteria :-

We reject null hypothesis is absolute value of calculated test statistics is greater than t-critical value tala

i.e Reject H0 if | TS | > tala

Here | TS | = | -2.251 | = 2.251 > 2.034              ( tala = 2.035 )

Thus | TS | > tala

So we reject null hypothesis at 0.05 level of significance .

Conclusion :-

We have sufficient evidence to reject the claim that this sample coins come from a population with a mean weight of 2.5 g

Hence correct option for conclusion is :-

Option C. Reject H0 , there is sufficient evidence to rejection of the claim that sample is from population with a mean weight equal to 2.5 g

Now since we have rejeted null hypothesis , so coins do not appears to confirm to the specification , since sample is from population with a mean weight different from 2.5 g

Hence correct option is

Option D. N0 , since the coins seems to be come from a population with a mean weight different from 2.5 g

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