Given
n = 34 ( sample of 34 coins are collected )
= 2.49507 ( sample coins have mean weight of 2.49507 g )
s = 0.01277 ( sample standard deviation is 0.01277 g )
To Test :-
H0 : = 2.5 ( sample coins come from a population with a mean weight of 2.5 g )
H1 : 2.5 ( sample coins may not come from a population with a mean weight of 2.5g )
{ Note that all options patterns are not visible in given image , so can't determine which option have correct above pattern }
Test statistics :-
TS =
=
TS = -2.251104
Hence , calculated test statistics value is TS = -2.251
To find critical value :-
Since alternative hypothesis is of "" type , so these is two-taile t-test,and thus t-critical value will be given by
Here is t-distributed with n-1 = 34-1 = 33 degree of freedom and =0.05,
It can be computed from statistical book or more accurately from any software like R,Excel
From R
> qt(1-0.05/2,df=33)
[1] 2.034515
Thus = 2.035
The critical value is 2.034
Rejection criteria :-
We reject null hypothesis is absolute value of calculated test statistics is greater than t-critical value
i.e Reject H0 if | TS | >
Here | TS | = | -2.251 | = 2.251 > 2.034 ( = 2.035 )
Thus | TS | >
So we reject null hypothesis at 0.05 level of significance .
Conclusion :-
We have sufficient evidence to reject the claim that this sample coins come from a population with a mean weight of 2.5 g
Hence correct option for conclusion is :-
Option C. Reject H0 , there is sufficient evidence to rejection of the claim that sample is from population with a mean weight equal to 2.5 g
Now since we have rejeted null hypothesis , so coins do not appears to confirm to the specification , since sample is from population with a mean weight different from 2.5 g
Hence correct option is
Option D. N0 , since the coins seems to be come from a population with a mean weight different from 2.5 g
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