Question

Question 39 5 pts Use your calculator to duplicate the following table data as a matrix and conduct a X2 Test of Independence on your TI 83/84 device. Find the x2 (chi-square) value and P-value from these results. Cite my P-value for your answer. 252 24 208 23 my P-value = O My P-value is about 0.238 My P-value is about 0.762 O My P-value is about 0.374 O My P-value is about 0.626

Answer 1

Hello

	Observed Values
		Column Title
		C1	C2	Row Total
Row Title	R1	252	24	276
R2	208	23	231
	Column Total	460	47	507
	Expected Values
		Column Title
		C1	C2	Row Total
Row Title	R1	250.414	25.586	276
R2	209.586	21.414	231
	Column Total	460	47	507
	Difference
		Column Title
		C1	C2	Row Total
Row Title	R1	0.010	0.098	0.108
R2	0.012	0.117	0.129
	Column Total	0.022	0.216	0.238

Q - 1 - OPTION D : 0.626

df	1
Chi-square Test Statistic	0.238
Critical value	0.626

Q - 2 - OPTION B : Greater, Accept

As p-value (0.626) > 0.05, hence, we accept the null (fail to reject the null)

Thanks!

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