Question

Drawing Canvas STE Ink to Ink to Shape Math Drawing Tools Convert Thermochemistry: Specific Heat Capacity Data Ink Replay Replay Insert Part I. Determination of the Specific Heat Capacity of a metal. Table 1. Experimental Data. Amount of Heat Run No. Material Mass (g) Initial T("C) Fira IPC) Absorbed/Released (use signs) (J) H2O 1 Au H2O N 64.000 25.00'c 25.7890 38.60g 65. 17°C 25.78 °C 164.00g /25.00°C/25.70°C 17.929 53.9906/25.7890 64.00g /25.0000 25.700 15.74953.30°025.78°C Cu H2O Fe Table 2. Experimental Results. Experimental True Run No. Material Specific Heat, Specific Heat, s $ (J/g...) (J/9..c) % Error 1 Au 2 Cu D. Focus 00 O Prt Sche Home F5 $ % & 6 7 oc

Answer 1

Run 1

Heat absorbed by water = Mass x Cpw x temperature change

= 64 g x 4.184 J/g-°C x (25.78 - 25)°C

= 208.86528 J

Heat released by Au = - Heat absorbed by water = Q1

-208.86528 J = Mass x C1 x temperature change

-208.86528 J = 38.60 g x C1 x (25.78 - 65.17)°C

C1 = 0.1374 J/g-°C

Run 2

Heat absorbed by water = Mass x Cpw x temperature change

= 64 g x 4.184 J/g-°C x (25.78 - 25)°C

= 208.86528 J

Heat released by Cu = - Heat absorbed by water = Q2

-208.86528 J = Mass x C2 x temperature change

-208.86528 J = 17.92 g x C2 x (25.78 - 53.99)°C

C2 = 0.4132 J/g-°C

Run 3

Heat absorbed by water = Mass x Cpw x temperature change

= 64 g x 4.184 J/g-°C x (25.78 - 25)°C

= 208.86528 J

Heat released by Fe = - Heat absorbed by water = Q3

-208.86528 J = Mass x C3 x temperature change

-208.86528 J = 15.74 g x C3 x (25.78 - 53.3)°C

C3 = 0.4822 J/g-°C

Run 1

%error for Au = (C1 - C1') * 100/C1'

= (0.1374 - 0.126) * 100/0.126

= 9.047%

Run 2

%error for Cu = (C2 - C2') * 100/C2'

= (0.4132 - 0.385) * 100/0.385

= 7.325%

Run 3

%error for Fe = (C3 - C3') * 100/C3'

= (0.4822 - 0.444) * 100/0.444

= 8.604%