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5) Intelligence as measured by IQ tests is normally distributed with a mean 100 and standard deviation 15. Suppose groups of

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= 100, 0 = 15, n = 10 Pr(105 < X < 110) X1 - M 21 105 100 15/V10 = 1.0541 oln 110 - 100 Z2 X2 – M o/vn 2.1082 15/10 Pr(105 <from the calculation we can say 12.84% of these groups are having IQ between 105 and 110

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