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Solve the problem. Round three decimal places as needed. Intelligence Quotient (IQ) scores are normally distributed with a me

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TABLE III. THE NORMAL PROBABILITY INTEGRAL O I 2 3 4 5 6 8 9 o oo OI 02 03 0.4 50000 49601 49202 48803 48405 46017 45620 452I am attaching the normal table P(Z>z).

If XN+/100, 15² Nf 10, 11 the XNl 100 P(los < X <110) PL 105-100 LZ< llo-loo 1513 110-120] 1513 2 =PLIS 2 La PORODOS p(221) -

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