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4. Shown below are a titration curve and reaction coordinate diagram for the neutralization of 25.0 mL of a weak acid with Na
c. Calculate the pK, of HA at 25°C. (10 pts) Answer: d. The titration is repeated at 10°C, using the same initial molarities
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An la) HA of Nach -> NaH AH O - rate constant K 2050 mg ap unit of rate constant is ms so it is harder reaction r=K[HA][naPka 5 from and o initial mo lacrity coolm @ the value of [Pka =5 (HA); Foolm At equivalence point. (MN) - (m2/2) NAOH 0.125 =2.5 mmole usmL >) 18 Now due to salt hydrolys PH = 1/2 PKW pka + loge 날 P ļ [14.54+5+ log 18 PH=9.14 please give the thumbs u

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