Question

Giveni VA = 2 m/s down 0.3m incline 28 Find VB, JAS Usial a different methods solve this is vector 22 2) I.C. 3 graphical

Answer 1

VA= 2 m/s 863 0.3m d = 0.3 Lé 20 (1) using rector diagram, V68 10 O As using sine rule in rector diagram. B sinso sinfo - V = VA sinso sinfo Jo = 1.631m's (to the न sight) WAR e VAB from rektor diagram, VAB - 1.8432 m/s sino sinto NAB WAB 1.8432 0.3 = 6-144 radls (considering Alw direction as tve) Direction of w WAB is decided by considering B at rest with respect and then watching the relocity of A to B.

(2) Using I-centre method. Considering it to be double slides motion. . 13 112 Sy 3. 20 40 70 20° 230 123 A Ho. of link 24 20. of I-centre = » (n-1) = 4(3) = 6 We will find IB using kenedy theoram 1,2 123 I13 will be in line with • Izy [134 A = V22y = W3 ( 113 I34) 190) from 223 224 [13, using sive rule, [13 134 I23 I34 singo I z £23 (23 134 - AB=0.3) sinto sin so 0.32552 m a [13534 and I 13 123 0.265365 m putting value of I13I34 in e 2 6.144 rad's (Acw) W3 = 0.32532 direction of wo decided by direction of VA.

W3 = WAB so WAB 6.144 radls (Acw) ol v W3 (113 [23) 123 6-144 (0.265365) VaR 1-63 mis (to the right)