Question

A ski starts from rest and slides down a 28 degree incline 60 m long.

a) If the coefficient of friction is 0.090, what is the ski's speed at the base of the incline?

b) If the snow is level at the foot of the incline and has the same coefficient of friction, how far will the ski travel along the level? Use energy methods.

Answer 1

Given that Q = 2 r degree Incline = 60 m coefficient of friction = 0.090 (a) Initial P.E = Final K.E + work done against Friction M V^2/2 + u mgs cos (a) = mgs sin (a) V^2 = 2 g s (sin (a) - u cos (a)) V = [(2 times 9.81 times 60 (sin (28) - 0.09 cos (28))] = 21.42 m/s (b) MV^2/2 = u mgs s = V^2/2 ug = (21.42)^2/2 times 0.09 times 9.81 = 260 m